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1000=16k^2-k
We move all terms to the left:
1000-(16k^2-k)=0
We get rid of parentheses
-16k^2+k+1000=0
a = -16; b = 1; c = +1000;
Δ = b2-4ac
Δ = 12-4·(-16)·1000
Δ = 64001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{64001}}{2*-16}=\frac{-1-\sqrt{64001}}{-32} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{64001}}{2*-16}=\frac{-1+\sqrt{64001}}{-32} $
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